INFIX TO POSTFIX EXPRESSION

1001

bca

infix to ppostfix expression

third semester

program

 

 

#include<stdio.h>
#include<math.h>
char inf[30],postf[30];
int st[30],i=0,j=0,top=-1;
void push(int);
char pop();
main()
{
clrscr();
st[top]=0;
printf(“Enter infix expression : “);
gets(inf);
while(inf[i]!=NULL)
{
switch(inf[i])
{
case ‘(‘:
push(0);
break;
case ‘+’:
while(st[top]>=1)
{
postf[j++]=pop();
}
push(1);
break;
case ‘-‘:
while(st[top]>=1)
{
postf[j++]=pop();
}
push(2);
break;
case ‘*’:
while(st[top]>=3)
{
postf[j++]=pop();
}
push(3);
break;
case ‘/’:
while(st[top]>=3)
{
postf[j++]=pop();
}
push(4);
break;
case ‘^’:
while(st[top]>=5)
{
postf[j++]=pop();
}
push(5);
break;
case ‘)’:
while(st[top]!=0)
postf[j++]=pop();
top–;
break;
default:
postf[j++]=inf[i];
}
i++;
}
while(top>-1)
{
postf[j++]=pop();
}
postf[j]=NULL;
printf(“Postfix expression : “);
puts(postf);
getch();
}
void push(int p)
{
st[++top]=p;
}
char pop()
{
int op;
op=st[top–];
switch(op)
{
case 1:
return ‘+’;
case 2:
return ‘-‘;
case 3:
return ‘*’;
case 4:
return ‘/’;
case 5:
return ‘^’;
}
}

OUTPUT

Enter infix expression : A + (B * C)
Postfix expression : B C * A +

 

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